请各位大神帮我用java编一下这个程序吧...我一点头绪都没有...

这道题的答案是：x=1.364746094

http://wenku.baidu.com/link?url=wjIO2baxEfcSucwWaY_acszu0735F0QeyzjGf-Vrkr6R0xLvWnExVQSjPHb-4AX541nAiEoAaJGrH7V2aGTaoURkYFxRmydDCzkk5XcVgTS
http://download.csdn.net/detail/u012724893/8289089

public class demo{
public static void main(String[] str){
double a1 = 1, b1 = 2;

  double x1 = 1;
  double x2 = (a1 + b1) / 2;
  //c存储前一个x2值
  double c = 0 ;
  double check = 1;
  while(check >= 0.00005){
      x2  = (a1 + b1)/2.0;
      check = Math.abs(x2 - c); 
      double result = Math.pow(x2, 3) + 4 * Math.pow(x2, 2) - 10;          
      if(result > 0){
          b1 = x2; a1 = x1; c = x2;
      }
      else {
          a1 = x2;
          c = x2;
      }

  }

 System.out.println(x2);
}

}
输出为
1.3652290927316866

可能不同的编译器对数据的处理不一样，你这明显是c语言书。。程序逻辑有问题

public class demo {

public static void main(String[] str) {

double a1 = 1, b1 = 2;

    double x1 = 1;  
    double x2 = (a1 + b1) / 2;  
    // c存储前一个x2值  
    double c = 0;  
    while (Math.abs(x2 - c) >= 0.00005) {  

        double result = Math.pow(x2, 3) + 4 * Math.pow(x2, 2) - 10.0;  
        if (result > 0) {  
            b1 = x2;  
            a1 = x1;  
            c = x2;  
        } else {  
            a1 = x2;  
            c = x2;  
        }  
        x2 = (a1 + b1) / 2.00;  
    }  
    System.out.println(x2);  
}  

}

稍微改了一下

其实你输出的d是方程的值，并不是根，我们要输出的是根值，比较的也是根的灵敏度，对二分法没有理解啊！！

当然我的做法也有一点不严谨，具体哪一点可以自己思考，也可以参考@caozhy 提供的链接

public static void main(String[] args) {
double a1 = 1.0, b1 = 2.0;

        double x1 = 1.0;  
        double x2 ;   
        while (Math.abs(b1 - a1) >= 0.0005) {  
            x2 = (a1 + b1) / 2; 
            double result = Math.pow(x2, 3) + 4 * Math.pow(x2, 2) - 10.0;  
            if (result > 0) {  
                b1 = x2;  

            } else {  
                a1 = x2;                    
            }  

        }  
        System.out.println(a1);
     }
    又仔细看了一下，发现以前理解错了，这次输出是1.36474609375

这个程序你可以自己在完善下