c#里面这个Date(1420335269000+0800)如何转换为datetime类型
long unixDate = 1420335269000;
DateTime start = new DateTime(1970, 1, 1, 0, 0, 0, DateTimeKind.Utc);
DateTime date= start.AddMilliseconds(unixDate).ToLocalTime();
date.Dump(); //1/4/2015 9:34:29 AM
/// <summary>
/// 时间戳转为C#格式时间
/// </summary>
/// <param name=”timeStamp”></param>
/// <returns></returns>
private DateTime GetTime(string timeStamp)
{
DateTime dtStart = TimeZone.CurrentTimeZone.ToLocalTime(new DateTime(1970, 1, 1));
long lTime = long.Parse(timeStamp + "0000000");
TimeSpan toNow = new TimeSpan(lTime); return dtStart.Add(toNow);
}
/// <summary>
/// DateTime时间格式转换为Unix时间戳格式
/// </summary>
/// <param name=”time”></param>
/// <returns></returns>
private int ConvertDateTimeInt(System.DateTime time)
{
System.DateTime startTime = TimeZone.CurrentTimeZone.ToLocalTime(new System.DateTime(1970, 1, 1));
return (int)(time - startTime).TotalSeconds;
}
你的代码不需要加后面的0
谢谢兔子党-督察 和caozhy的回答!经过二位的答案,我整合了一下,OK了!谢谢