新手。。
写了个登陆微博的小demo,获取token后打算跳转到别的页面,
- (void)sinaweiboDidLogIn:(SinaWeibo *)sinaweibo
{
[self saveWeiboInfo];
NSLog(@"uid= %@ accessToken= %@", sinaweibo.userID, sinaweibo.accessToken);
[self performSegueWithIdentifier:@"login" sender:self];
}
获得token后报错:
2013-02-18 17:31:50.683 WeiboTimeline[5690:c07] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'Receiver (<WeiboLoginViewController: 0x712a850>) has no segue with identifier 'login''
segue的identifier已经设置好了
但是。。在viewdidLoad里,很奇怪的却能跳转
- (void)viewDidLoad
{
[super viewDidLoad];
NSDictionary *dic = [[NSUserDefaults standardUserDefaults] dictionaryForKey:@"weiboUserData"];
NSString *token = [dic valueForKey:@"access_token"];
NSLog(@"token= %@", token);
if (token != nil) {
[self performSegueWithIdentifier:@"login" sender:self];
}
}
上面这样,token获取了保存后,下次再打开应用就能跳转。。
明明是一样的代码。。为什么上面那个报错。。。求解
http://blog.csdn.net/liangguo03/article/details/7956163
你参考一下这个调试的文章