转换数字为指示性字符

我从数据库中得到的数据是1，2，3这样的格式，我想在标签中显示为one，two这样，应该怎么实现？

谢谢

换一下就行，

public static void main(String[] args)
{
//这里有定义成一个数组...这样才方便
String x[]={"zero","one","two", "three","four", "five","six","seven","eight","nine",
"ten","eleven","twelve","thirteen","fourteen","fifteen", "sixteen","seventeen","eighteen","nineteen",
"twenty","thirty","fourty","fifty", "sixty","seventy", "eighty","ninety"
} ;

Scanner in = new Scanner(System.in);
String s;
s = in.next();//这里用 next()方法
int j=0;

for(int i=0 ; i<x.length; i++ )
{
if(s==x[0])
{
//这里判断 如果输入的字符串有和你数组里定义的字符串有相同的 就跳出
//需要注意的是数组的索引是从0开始的所以对应的数组要+1
j=i+1;
}
}
System.out.println("你输入的数字是"+j);

}

如果全部是10以内的数，是比较好处理。最笨的方法就是定义一个数组来存储英文串

-(NSString *)convertToEnglish:(int) num {
   NSArray *array=@{@"zero",@"one",@"two",@"three",@"four",@"five",@"six",@"seven",@"eight",@"nine"};
/////得到数字是几，就用几当下标索引去数组中查找就可以了
   NSLog(@"get english is :%@",[array objectAtIndex:num]);
}

如果是大于10的就要另写算法来处理了

NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
[formatter setNumberStyle: NSNumberFormatterSpellOutStyle];
NSString* numberString = [formatter stringFromNumber:[NSNumber numberWithInt:3]];
NSLog(@"%@",numberString);

试试这样替换值。