<%@ page language="java" pageEncoding="gbk"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<base href="<%=basePath%>">
<title>My JSP 'error.jsp' starting page</title>
<meta http-equiv="pragma" content="no-cache">
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="expires" content="0">
<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
<meta http-equiv="description" content="This is my page">
<!--
<link rel="stylesheet" type="text/css" href="styles.css">
-->
</head>
<body>
<font color="#rrddb">操作失败！</font> <br>
</body>
</html>
显示<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
模块出现错误，不知道怎么解决，请求高手。大家帮帮忙啊，在此谢谢了。
如果删除<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>就会显示<base href="<%=basePath%>">错误。
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
这几行擦掉就行~
<%
String path = request.getContextPath();
String basePath = request.getScheme() + "://"
+ request.getServerName() + ":" + request.getServerPort()
+ path + "/";
%>
代码没错，你试试关掉文档，清理缓存，再打开，试试~~
<%String path = request.getContextPath();String basePath = request.getScheme()+"://"+ request.getServerName() + ":" + request.getServerPort()+path + "/";%>
request.getScheme() //返回协议名（http）
request.getServerName() //返回IP地址（127.0.0.1）
request.getServerPort() //返回端口号（8080）
request.getContextPath() //返回项目的路径（myweb/admin）
目的是为了得到，请求这个页面的绝对路径
<base href="<%=basePath%>">
的意思是把所有请求都按照这个路径提交.例如有一个超链接
<a href="index.jsp"></a>
那么请求的时候就会是绝对路径http：//127.0.0.1:8080/myweb/admin/index.jsp
而不是相对路径。
希望对你有帮助~~~~