def secret(numbers):
for index in range(len(numbers)):
if numbers[index] == index:
return 0
return 1
选项 :
A [8, 3, 8, 4, 7]
B[3, 0, 9, 4, 2]
C[1, 1, 4, 9, 7]
D[3, 3, 0, 5, 6]
E[4, 6, 9, 4, 8]
C[1, 1, 4, 9, 7]
列表的下标索引和range()的起始都是从0开始的,因此简单的数下就可以知道,[1, 1, 4, 9, 7]会返回0