带有类别搜索的ajax php

Hello I am developing an ajax php search. It will search through the database accross multiple tables when someone types. My question is that i need it to bring up a name like if someone types the name Apple tv i want it to bring up do you want the category or the specific product?. How can i do that?

This is what I have so far:

<?php
//Database values
$host = "localhost";
$dbname = "tool";
$user = "root";
$password = "root";
$database = new mysqli();

$database->connect($host, $user, $password, $dbname);

//Kill website if database connection fails
if($database->connect_errno) {
die("Database connection failed.");
}

//Connect to the database
//Clean user input
$search = $database->real_escape_string($_POST['search']);
$search = preg_replace("/[^A-Za-z0-9 ]/", '', $search);
$search = "'%".$_POST['search']."%'";

$query = "SELECT * FROM brands WHERE braname LIKE $search ORDER by braname ASC LIMIT 5";

if($results = $database->query($query)){
while ($player = $results->fetch_assoc()){
echo "<div class='col-sm-4' id='adjust-Searchbox'>" . "<a href=\"users/e-commerceTemplateSingleBrand.php?braid=".$player['braid']."\">" . "<p>" . $player["braname"] . "</p>" . "<img style='width:100%; height:50px;' src=\" uploads/".$player['braimg']."\">" . "</a>" . "</div>"

;
}
}else{
die("Database connection failed.");
}

$search = $database->real_escape_string($_POST['search']);
$search = preg_replace("/[^A-Za-z0-9 ]/", '', $search);
$search = "'%".$_POST['search']."%'";

$query = "SELECT * FROM Products WHERE name LIKE $search ORDER by name ASC LIMIT 5";

if($results = $database->query($query)){
while ($player = $results->fetch_assoc()){
echo "<div class='col-sm-4' id='adjust-Searchbox'>" . "<p>" . $player["name"] . "</p>" . "<img style='width:100%; height:50px;' src=\" uploads/".$player['proimg']."\">" . "</br>" . "</div>";
}
}else{
die("Database connection failed.");
}

Create the search text field

<input onkeyup="do_search();" type="text" value="" id="search_string">

Then add your javascript to call the ajax

function do_search() {
$('#the_div_to_show_ajax_return').html('Please wait ...');
$.ajax({
type: "POST",
url: "yourcode.php",
data: {search: $('#search_string').val()}
})
.done(function( msg ) {
    $('#the_div_to_show_ajax_return').html(msg);
});
}

Also make sure you have a div ready for the results

<div id="the_div_to_show_ajax_return"></div>