点击按钮提交ajax表格

http://jsfiddle.net/pdb26p3q/22/

$(".verify").click(function () {

    var ID = $(this).attr('id');
    var dataString = 'verify=' + ID;

    $.ajax({
        type: "POST",
        url: "",
        data: dataString,
        cache: false,
        success: function () {
            $(".code").show('slow');
        }
    });
});

I have tried using my own server and is not working too

I'm not sure what is the problem, sorry Im quite near to jquery

Edited: The .code(input) is not showing. Because if submit successfully the input will be shown.

you can try like

var dataString = {verify:ID};