I have a for
statement to create 20 number of forms, but after creating elements my forms look like empty(but I have input elements on it) and that is why I cannot send objects with POST.
<form method="post" ></form>
this is my code :
for($i= 1 ; $i<=$numtest ; $i++){
$mdata = $numtoword->ToWordFa($i);
echo '
<li>
<div class="questitle2 noselect"><a href="#">عنوان سوال '.$mdata.'</a></div>
<div class="quescontent">
<input type="text" class="questitle byekan" name="tt'.$i.'" id ="tt'.$i.'" placeholder="عنوان سوال '.$i.'" onclick="select()" /><br/>
<div style="text-align:right;margin-top:10px;" class="qkind">نوع سوال :
<input type="radio" name="istest'.$i.'" id="is2test'.$i.'" value="yt2" onclick="add_choice(\'c'.$i.'\' , \'yt2\');" /><label for="is2test'.$i.'"><span class="noselect fade"> 2 گزینه ای</span></label>
<input type="radio" name="istest'.$i.'" id="is4test'.$i.'" value="yt4" onclick="add_choice(\'c'.$i.'\' , \'yt4\');" /><label for="is4test'.$i.'"><span class="noselect fade"> 4 گزینه ای</span></label>
<input type="radio" name="istest'.$i.'" id="nottest'.$i.'" value="nt2" onclick="add_choice(\'c'.$i.'\' , \'nt2\');"/><label for="nottest'.$i.'"><span class="noselect fade"> تـشریحی</span></label>
</div>
<form method="post" >
<input type="hidden" name="tid1" value="'.$tkey.'"/>
<input type="hidden" name="thisquestion1" value="'.$i.'"/>
<div class="choosepart" id="c'.$i.'"></div>
<div id="res"> </div>
<input class="fade" id="sc'.$i.'" style="margin-top:5px;" type="button" name="Send" onclick="formget( this.form , \'tests.php\' , \'res\' , \'dd\' ,\''.$i.'\');" value="ثبت این سوال" disabled/>
</form>
</div>
</li>
';
}
Ajax will put input elements in this div of above code :
<div class="choosepart" id="c'.$i.'"></div>
how can moderate that?
thanks in advance
Please place below code after for
statement, this code will tell you what/where is the issue/error. Let me know if require more help from us.
//This code will suggest what/where is the error
print("<pre>");
print_r(error_get_last());
print("</pre>");
Hope this helps you.
Thanks!
When you use ::
you are trying to access a method statically so your function signature should be declared as: public static function toWord2()
.
I think you defined your method toWord2
as non-static and you are trying to invoke it as static. That said.
1) If you want to invoke a static method, you should use the ::
and define your method as static.
// Defining a static method in a Foo class.
public static function toWord2() { /* code */ }
// Invoking that static method
NumericHelper::toWord2();
2) otherwise, if you want to invoke an instance method you should instance your class, use ->
.
// Defining a non-static method in a Foo class.
public function toWord2() { /* code */ }
// Invoking that non-static method.
$objNumericHelper = new NumericHelper();
$objNumericHelper->toWord2();
You can ride same thing about OOP & static methods in PHP