Ajax表单提交响应

I am having trouble with the function ShowResponse action on my Ajax Form. I am trying to show a simple message in the #show div once the form has been submitted. The Ajax submission is working okay and I can get an alert to work but I cant get the #show div to display. My code looks like this,

<script type="text/javascript" src="/uploads/JS/jquery.form.js"></script>

<script type="text/javascript"> 
$(document).ready(function() { 

var options = { 
target:        '#contact_form_94',
success:       showResponse
}; 

$('#m477famoduleform_2').ajaxForm(options); 
}); 

function showResponse(responseText, statusText, xhr, $form)  { 
    alert('status: ' + statusText + '

responseText: 
' + responseText + 
        '

The output div should have already been updated with the responseText.'); 
} 
</script> 

If anyone could help that would be great. As a minimum I would just like to replace the form with a 'Success' message.

Thanks

Chris

Does it work if you include the showResponse function within the $(document).ready?

If you are saying you can alert the response and can see it then I think #show does not exist on the page. Try to alert $('#show').length and see what you get.