有关xmlhttp.open的查询

Experts i need your help

Can i pass a server url in xmlhttp.open parameter list eg: xmlhttp1.open("GET","http://10.6.10.222/DEV/Cgate/dailystat.txt",true);

I am unable to pass a server url(second parameter) and get no response

Any url that can be accessed by the browser can be called using a ajax call.

If you can directly access your server in the browser then you can call it.

EDIT You cannot make a cross domain call. For that you need special permission set.