矩阵相加那块儿一直出错,看不出来哪里有问题
#include
int main(void) {
int A[3][3], i, j, sum;
for (i = 0; i <= 2; i++) {
for (j = 0; j <= 2; j++) {
printf("a[%2d]行[%2d]列", i, j);
scanf("%d", &A[i][j]);
}
}
for (i = 0; i <= 2; i++) {
for (j = 0; j <= 2; j++)printf("%4d", A[i][j]);
printf("\n");
}
int B[3][3], m, n, sun;
for (m = 0; m <= 2; m++) {
for (n = 0; n <= 2; n++) {
printf("a[%2d]行[%2d]列", m,n);
scanf("%d", &B[m][n]);
}
}
for (m = 0; m <= 2; m++) {
for (n = 0; n <= 2; n++)printf("%4d", B[m][n]);
printf("\n");
}
int C[3][3];
int k, l;
C[k][l] = A[i][j] + B[m][n];
printf("\n");
for (k = 0; k < 3; k++)
{
for (l = 0; l < 3; l++)
printf("%5d", C[k][l]);
printf("\n");
}
return 0;
}
int main(void) {
int A[3][3], i, j;
for (i = 0; i <= 2; i++) {
for (j = 0; j <= 2; j++) {
//printf("a[%2d]行[%2d]列", i, j);
printf("a[%d][%d]=", i, j);
scanf("%d", &A[i][j]);
}
}
for (i = 0; i <= 2; i++) {
for (j = 0; j <= 2; j++)
printf("%4d", A[i][j]);
printf("\n");
}
int B[3][3], m, n;
for (m = 0; m <= 2; m++) {
for (n = 0; n <= 2; n++) {
//printf("a[%2d]行[%2d]列", m, n);
printf("b[%d][%d]=", m, n);
scanf("%d", &B[m][n]);
}
}
for (m = 0; m <= 2; m++) {
for (n = 0; n <= 2; n++)printf("%4d", B[m][n]);
printf("\n");
}
int C[3][3];
printf("\n");
for (int k = 0; k < 3; k++)
{
for (int l = 0; l < 3; l++) {
C[k][l] = A[k][l] + B[k][l];
printf("%5d", C[k][l]);
}
printf("\n");
}
return 0;
}
最后的时候借住二重循环,实现加法计算,貌似你对二重循环的理解不好,对变量的理解也不好。
#include
int main() {
int A[3][3], i, j, sum;
for (i = 0; i <= 2; i++) {
for (j = 0; j <= 2; j++) {
printf("a[%2d]行[%2d]列", i, j);
scanf("%d", &A[i][j]);
}
}
for (i = 0; i <= 2; i++) {
for (j = 0; j <= 2; j++)printf("%4d", A[i][j]);
printf("\n");
}
int B[3][3], m, n, sun;
for (m = 0; m <= 2; m++) {
for (n = 0; n <= 2; n++) {
printf("a[%2d]行[%2d]列", m,n);
scanf("%d", &B[m][n]);
}
}
//输出B
for (m = 0; m <= 2; m++) {
for (n = 0; n <= 2; n++)printf("%4d", B[m][n]);
printf("\n");
}
int C[3][3];
int k, l;
for (k = 0; k < 3; k++){
for (l = 0; l < 3; l++)C[k][l] = A[k][l] + B[k][l];
}
printf("\n");
for (k = 0; k < 3; k++){
for (l = 0; l < 3; l++)printf("%5d", C[k][l]);
printf("\n");
}
return 0;
}