我国古代数学家在《算经》中出了一道题：鸡翁一，值钱五；鸡母一，值钱三；鸡雏三，值钱一。百钱买百鸡，问鸡翁、母、雏各几何？”意为公鸡4吊钱1只，母鸡3吊钱1只，3只小鸡值1吊钱。编程实现用100吊钱买100只鸡，公鸡、母鸡、小鸡每种鸡至少一只，有多少种买法？(2)
Private Sub command1_Click()
Dim a%, b%, c%, s%
FontSize = 14: FontBold = True
Print: Print: Print
s = 0
For a = 1 To 20
For b = 1 To 34
If 4 * a + 3 * b + c / 3 = 100 Then s = s + 1
Next b
Next a
Print s
End Sub
要将一张100元的大钞票，换成等值的10元、5元、2元和1元一张的小钞票。要求每次换成50张小钞票，每种至少一张。编程求有多少种换法。(26)
Private Sub Command1_Click()
Dim i, j, k, m As Integer
Dim RMBsum As Integer
FontSize = 14: FontBold = True
For i = 1 To 9
For j = 1 To 17
For k = 1 To 37
m = 50 - i - j - k
If Then RMBsum = RMBsum + 1
Next k, j, i
Print RMBsum
End Sub
#include <stdio.h> //引用头文件
int main()
{
int cock,hen,chick; //定义公鸡，母鸡，小鸡三个变量
int n = 0;
for(cock=1;cock<=20;cock++) //公鸡的范围在0 ~ 20之间；
for(hen=1;hen<=33;hen++) //母鸡的范围在0 ~ 33之间；
for(chick=1;chick<=99;chick++) //小鸡的范围在3 ~ 99之间
if(cock*15 + hen*9 + chick==300) // “百钱问题”
if(cock+hen+chick==100) //“百鸡问题”
{
printf("公鸡:%d,母鸡:%d,小鸡:%d\n",cock,hen,chick); //输出结果!
n++;
}
printf("%d", n);
}
公鸡:4,母鸡:18,小鸡:78
公鸡:8,母鸡:11,小鸡:81
公鸡:12,母鸡:4,小鸡:84
3
#include <stdio.h>
#include <stdlib.h>
int main()
{
int x3,x2,x1,x;
int n = 0;
for(x3=1;x3<=10;x3++)
{
for(x2=1;x2<=20;x2++)
{
for(x1=1;x1<=50;x1++)
{
for(x=1;x<=100;x++)
{
if((x3*10+x2*5+x1*2+x==100)&&(x3+x2+x1+x==50))
{
printf("%d\t%d\t%d\t%d\n",x3,x2,x1,x);
n++;
}
}
}
}
}
printf("%d\n", n);
}
1 1 37 11
1 2 33 14
1 3 29 17
1 4 25 20
1 5 21 23
1 6 17 26
1 7 13 29
1 8 9 32
1 9 5 35
1 10 1 38
2 1 28 19
2 2 24 22
2 3 20 25
2 4 16 28
2 5 12 31
2 6 8 34
2 7 4 37
3 1 19 27
3 2 15 30
3 3 11 33
3 4 7 36
3 5 3 39
4 1 10 35
4 2 6 38
4 3 2 41
5 1 1 43
26