I want to make a WEB page move screen transition in ajax . I wrote in one.html
<html>
<head>
<meta charset="UTF-8">
<title>Top</title>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script src="jquery.pjax.js"></script>
</head>
<script type="text/javascript">
$(function() {
$.pjax({
area: '#main'
});
$(document).bind('pjax:render', function() {
$('#main').attr({
'class': 'fadeInUp'
});
});
});
</script>
<body>
<p>
name
</p>
<input type="text" name="name" size="10">
<p class="button"><a href="two.html">Next</a></p>
</body>
</html>
in two.html
<p>
age
</p>
<input type="text" size="10">
<p class="button"><a href="three.html">Next</a></p>
But when I put Next button in one.html,Page not found (404) Request URL:http://127.0.0.1:8000/app/two.html error happens. I cannot understand why such an error happens.What is wrong in my codes?How should I fix this?
http://127.0.0.1:8000/app/two.html
so the link you can set blow:
<p class="button"><a href="app/two.html">Next</a></p>