date=2009/10/21
(4)转换日期格式为2009-10-21
请问java要实现这样的功能代码是怎么样的
Scanner scan = new Scanner(System.in);
String inputstr = scan.nextLine();
String[] arr = inputstr.split(" && ");
String name = arr[0];
String passwd = arr[1];
String datatime = arr[2];
if (!name.matches("^[a-zA-Z][a-zA-Z0-9]*$"))
System.out.println("姓名不合法");
if (!passwd.matches("[0-9]{6,20}"))
System.out.println("密码不合法");
datetime = datetime.replace('-', '/');
System.out.println(datetime);
(1) 假设字符串是str
String[] str1 = str.split("&&");
String name = str1[0].split()[0].equals("username=")?str1[0].split()[1]:null;
String passwd = str1[1].split()[0].equals("password=")?str1[0].split()[1]:null;
String datetime = str1[2].split()[0].equals("date=")?str1[0].split()[1]:null;
(2)
String reg = "^[a-zA-Z][a-zA-Z0-9]*$";
if (Pattern.matches(reg,name)){
System.out.println("匹配");
}
(3)
String reg = "[0-9]{6,20}";
if (Pattern.matches(reg,name)){
System.out.println("匹配");
}
(4)
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd");
Date date = new Date(datetime);
System.out.println(simpleDateFormat.format(date));
这不给个赞 我觉得说不过去了。
package com.company;
import java.util.Date;
public class Main {
public static void main(String[] args) {
String str="username=chen && password=12345 && date=2009/10/21";
String[] arr=str.split("&&");
String name=arr[0].split("=")[1];
String password=arr[1].split("=")[1];
String date=arr[2].split("=")[1];
//判断用户名是否满足规则
boolean n= name.matches("^[a-zA-Z][a-zA-Z0-9]*$)");
if (n==true)
{
//满足
}
//判断密码是否满足规则
boolean p=password.matches("[0-9]{6,20})");
//转换日期格式
String time=date.replace("/","-");
}
}