I have a mvc project, what I want to do is this:
I am sending an ajax request from my JS script. After processing it I want to redirect to a page with a model.
Now I tried sending a form as the ajax response and submit it like so:
sb.Append("<html>");
sb.AppendFormat(@"<body onload='document.forms[""form""].submit()'>");
sb.AppendFormat("<form name='form' action='{0}' method='post'>", "url..");
sb.AppendFormat("<input type='hidden' name='result' value='{0}'>", val1);
.....
And on the JS:
success: function (result) {
var form = $(result);
$(form).submit();
}
But this way i need to specify each post param, I want to send the entire model object. How can I do that?
Edit Full steps:
1.Using an MVC APP.
2.I submit button in my view which redirects the user to my JS code.
3.Js code sends an Ajax request to a MVC page called 'Transaction'.
4.C# code doing some actions and now I need to redirect the usr to a page named EOF with ALOT of post params, thats why I want to pass it as a ViewModel.
You can try this:
public ActionResult YourMethod(string param)
{
//what ever you want to do with reference no
return View("EOF");
// or, if you want to supply a model to EOF:
// return View("EOF", myModel);
}
As you are using ajax, you could return the URL from your action and have it redirected in javascript:
Controller
public ActionResult Transaction()
{
// Do stuff
return Json(new { success = true, redirecturl = Url.Action("RedirectedAction") });
}
Then add something like this to your success handler in javascript:
Javascript (within your success handler)
success: function (result) {
if (result.success == true)
{
window.location = result.redirecturl;
}
}