出现致命错误：mysqli

我正在努力将MySQL_Results替换为mysqli，有人能帮忙吗？我所需要的只是更正下面代码中的‘mysqli_Result($Result，’0‘，’theurl‘)。当使用MySQL函数编写所有东西时，它都能工作。但是，在我将所有内容转换为mysqli之后，MySQL_Results转换似乎就不起作用了。

当它工作时：echo(mysql_num_rows($query) !== 0) ? mysql_result($query, 0, 'theurl') : 'None';

当我运行当前代码时，我得到一个错误：Fatal error: Call to a member function data_seek() on a non-object in /home/abc/abc/test.php on line 15

<?php
    $getVal = "Record1";

    require '../db/connect.php';
    $query = ("SELECT 'photos'.'theurl' FROM 'photos' WHERE 'photos'.'thename' = '" . $getVal . "'");
    $result = mysqli_query($conn_db, $query);

    $queryA = ("SELECT id FROM photos");
    $resultA = mysqli_query($conn_db, $queryA);
    $row_cnt = $resultA->num_rows;

    echo($row_cnt !== 0) ? mysqli_result($result, '0', 'theurl') : 'Not found.'; // syntax meaning::  echo condition ? if TRUE output : if FALSE output; 

function mysqli_result($result, $ro, $field) { 
    $result->data_seek($ro); 
    $datarow = $result->fetch_array(); 
    return $datarow[$field]; 
}
?>

I think that you have a query error, you are using incorrect quote types, you will try:

$query = ("SELECT `photos`.`theurl` FROM `photos` WHERE `photos`.`thename` = '" . $getVal . "'") or die(mysqli_error($conn_db));

And, if you have a query problem, you can't get any result later.