I have a Tinybox 2 popup opening when clicking 'register'. The user has then to choose if he/she wants to register as a user or a performer. I'd like to show a different registration page for each, but first asking it, so handling with ajax would be the best. It can be done, as shown here, in the 5th example. Here is my current code:
<!doctype html>
<html>
<head>
<title>Regisztrációs típus kiválasztása</title>
<meta charset="utf-8"/>
<link rel="stylesheet" type="text/css" href="../css/soon.css"/>
<script type="text/javascript" src="../js/jquery-1.7.2.min.js"></script>
</head>
<body>
<div id="teljes">
<h1>Miként szeretnél regisztrálni?</h1>
<div id="felhasznalo">
<a href="#felhaszlano_regisztracio" id="felireg">Felhasználóként</a>
</div>
<div id="eloado">
<a href="../php/register_performer.php">Előadóként</a>
</div>
</div>
<script type="text/javascript">
$('#felireg').click(function() {
$.get("../php/register.php");
});
</script>
</body>
</html>
Thanks!
If i understand correctly, you want to make an ajax call to your registration file named "register.php" and show this in a Tinybox
$('#felireg').click(function() {
TINY.box.show({
url:'../php/register.php',width:300,height:150
})
});
This should work.
//EDIT : Assuming your file returns only html:
$('#felireg').click(function() {
$.get("../php/register.php", function(data)
{
TINY.box.fill(data);
});
});
This should update the current Tinybox