为什么会出现[Error] no matching function for call to 'Student::Student()'???

#include
#include
#pragma warning(disable:4996)
using namespace std;

class Person

{

protected:
char name[10];

char sex;
public:
Person(const char name[], char sex) :sex(sex)

{

    strcpy(this->name, name);

}

};

class DoubleArray

{

protected:

double score;

public:

DoubleArray(double score) :score(score) {}
DoubleArray(DoubleArray &a)

{

    score=a.score;
} 
void print() const
{

    cout << score;

}
int operator-()// 重载取反运算符 operator-,使Student类中的cheat函数可正确运行 

{

    return -score;

} 

};

class Student : public Person

{

private:

int id;
char name[20];
DoubleArray score;

public:
static int count;
~Student()
{

    count--; 

}

void cheat(DoubleArray& ds) 
{ 

    score = -ds; 

} // 若作弊，则分数为负
Student(Student &s,DoubleArray& sc);
Student(int id, const char* name, char sex, DoubleArray& sc);
Student(int id, const char* name, char sex, double ds);
void disp();

};
Student::Student(int id, const char* name, char sex, DoubleArray& sc):Person(name,sex),score(sc)
{

count+=1;

}
Student::Student(int id, const char* name, char sex, double ds):Person(name,sex),score(ds)
{

count+=1;

}
void Student::disp()
{

cout<<"(id, name, sex, score)="<<"("<<id<<","<<name<<","<<sex<<",";
score.print();
cout<<")"<<endl;

}
// 类外实现Student类的成员函数，令main函数得以正确运行并输出相应的结果
int main()
{

cout << "count=" << Student::count << endl;
DoubleArray sc(97);
Student s[3]={Student(1,"Ann",'F',sc),Student(2,"Mike",'M',79),Student(3,"Lucy",'F',sc)};
s[2].cheat(sc);
for (int i = 0; i < 3; i++)
s[i].disp();
cout << "count=" << Student::count << endl;
return 0;

}

解决办法：删除DoubleArray的拷贝构造函数。

同Xcode警告 !No matching constructor for initialization of 'Student'同问啊！为什么说** 没有用于初始化“Student”的匹配构造函数**

（宁也是大车埋土学校的？
btw说一个小问题你的两个student构造函数id没初始化 id(id)

在student的类里加一个构造函数

Student ():Person("",'M'),score(0.0){}