C++ 字符串的拼接的问题

std::string path = "d:\a\b\" ;这是路径
wstring filename=L"h1";这是文件的名字
最终我想要的是d:\a\b\h1.txt 这个完整的路径

std::string WStringToString(const std::wstring &wstr)
{
    std::string str;
    int nLen = (int)wstr.length();
    str.resize(nLen, ' ');
    int nResult = WideCharToMultiByte(CP_ACP, 0, (LPCWSTR)wstr.c_str(), nLen, (LPSTR)str.c_str(), nLen, NULL, NULL);
    if (nResult == 0)
    {
        return "";
    }
    return str;
}

...............................................................
std::string path = "d:\\a\\b\\" ;
wstring filename=L"h1";
path=path+WStringToString(filename)+".txt";

#include <bits/stdc++.h>
#include <iostream>
#include <stdio.h>
using namespace std;
char name[1000000], path[1000020] = {'d', ':', '\\', 'a', '\\', 'b', '\\'};
void finishname() {
    memset(name, '\0', sizeof(name));
    gets(name);//获取用户输入
    int n = strlen(name); /*char求长度*/
    for (int i = 0; i < n; ++i) {
        path[i + 7] = name[i];
    }
    int n2 = strlen(path); /*char求长度*/
    path[n2] = '.';
    path[n2 + 1] = 't';
    path[n2 + 2] = 'x';
    path[n2 + 3] = 't';
    n2 = strlen(path); /*char求长度*/
    // printf("%d\n", n2);//调试
    for (int i = 0; i < n2; ++i) {
        cout << path[i];//输出,如果不需要可以去除,如果要打开文件可以参考下面
    }
    /*
        system(path);//打开文件
    */
    return;
}
int main() {
    finishname();
    return 0;
}

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