JAVA拦截客户端的请求，华为无解，求高手帮破

为政府做报名项目，为了安全起见，对于获取不到真实IP地址的请求，我们做了拦截，
现发现华为的部分型号手机发起的请求无法获取到IP,
求教，这个要怎么破呢？

public static String Get_ip_address(HttpServletRequest request) {    
        String ip = request.getHeader("X-Forwarded-For"); 

        if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {  
            if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {  
                ip = request.getHeader("Proxy-Client-IP");  
            }  
            if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {  
                ip = request.getHeader("WL-Proxy-Client-IP");  
            }  
            if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {  
                ip = request.getHeader("HTTP_CLIENT_IP");  
            }  
            if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {  
                ip = request.getHeader("HTTP_X_FORWARDED_FOR");   
            }  
            if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {  
                ip = request.getRemoteAddr();   
            }  
            return ip;
        }
        if (ip.length() > 15) {  
            String[] ips = ip.split(",");  
            for (int index = 0; index < ips.length; index++) {  
                String strIp = (String) ips[index];  
                if (!("unknown".equalsIgnoreCase(strIp))) {  
                    return strIp;  
                }  
            }  
        }
        return null;  
    }

首先调试输出下X-Forwarded-For Proxy-Client-IP WL-Proxy-Client-IP这些，或者整个输出下header的值，看看HW的浏览器有什么不同
警惕，你应该同时记录代理ip和物理ip（ip = request.getRemoteAddr(); 看上去这个是物理ip），因为前者很容易伪造。