利用C++语言的移位运算实现左旋转移位。
#include
//val左旋转移n位，1<=n<=7
unsigned char rol(unsigned char val,int n);
//val左旋转移位(rol函数被重载)
unsigned char rol(unsigned char val);
//输出val对应的二进制值
void showBit(unsigned char val);
int main() {
unsigned char x=0xb5;
showBit(x); //输出x对应的二进制值
showBit(rol(x)); //输出x左移1位后对应的二进制值
int n;
std::cin>>n;
showBit(rol(x,n)); //输出x左移n位后对应的二进制值
return 0;
}
unsigned char rol(unsigned char x,int n) {
}
unsigned char rol(unsigned char val) {
}
void showBit(unsigned char val) {
}
输入
1<=正整数<=7
输出
10110101B 01101011B 左移n位后对应的二进制值B
class Solution {
public:
string LeftRotateString(string str, int n) {
int length=str.length();
if(length<0)
return NULL;
string tmp;
for(int i=0;i<n;i++)
{
tmp[i]=str[i];
}
for(int i=0;i<length-n;i++){
str[i]=str[i+n];
}
for(int i=length-n,a=0;i<length;a++,i++){
str[i]=tmp[a];
}
return str;
}
};