java8如何取数组中对象的值？？？

有这样一个数组：
[{0=1}, {0=2}, {0=3}, {0=4}, {0=5}, {0=6}, {0=7}, {0=8}, {0=9}, {0=10}, {0=11}, {0=12}, {0=13}, {0=14}, {0=15}, {0=16}, {0=17}, {0=18}, {0=19}]
现在只想要[1,2,3,4...]要怎么方便取出来啊？？？

List<String> collect = arr.stream().map(x->x.split("=")[1]).collect(Collectors.toList());

//利用正则表达式截取=号后面的值
Pattern p = Pattern.compile("\\{.+=(.+)\\}");

List<String> collect = Stream.of(new String[]{"{0=1}", "{0=12}", "{0=123}", "{1=1234}", "{1=1245}"}).map((s) -> {
        Matcher matcher = p.matcher(s);
        //group(1)表示正则表达式中第一对括号里的值
        return matcher.find()?matcher.group(1):null;
}).collect(Collectors.toList());

//打印结果
collect.stream().forEach(System.out::println);

public class TestDemo {
    public static void main(String args[]) {
        List list = new ArrayList();
        String string = "[{0=1}, {0=2}, {0=3}, {0=4}, {0=5}, {0=6}, {0=7}, {0=8}, {0=9}, {0=10}, {0=11}, {0=12}," +
                " {0=13}, {0=14}, {0=15}, {0=16}, {0=17}, {0=18}, {0=19}]";
        Pattern pattern  = Pattern.compile("\\{.*=[0-9]+\\}");
        // 这个是这么匹配的 。。。。
        Matcher matcher = pattern.matcher(string);
        if(matcher.find()){
            String group = matcher.group();
            String[] split = group.split(",");
            for(int i =0;i<split.length;i++){
                split[i] = split[i].replace("}","").trim();
                list.add(split[i].substring(3));
                                //这个3 是因为你前面都是{0=所以直接这样写的
            }
        }
        System.out.println(list);
    }
}

java的正则感觉好难用。