This question already has an answer here:
In PHP we have the list() which enable us to assign values to a list of variables in one operation. Eg:
list($a, $b) = ['valueA', 'valueB'];
echo $a; # valueA
echo $b; # valueB
Is it possible do the same thing in Go? Functions like Regexp.FindStringSubmatch() returns an array, so would be nice map this values directly into other variables.
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You cannot do that in go, but there is a way to achieve that by taking advantage the pointer value of it's variable.
Create a function, pass pointer of all receiver variables as slices, then re-assign the value.
func main() {
var arr = []string{"value 1", "value 2", "value 3"}
var a, b, c string
vcopy(arr, &a, &b, &c)
fmt.Println(a) // value 1
fmt.Println(b) // value 2
fmt.Println(c) // value 3
}
func vcopy(arr []string, dest ...*string) {
for i := range dest {
if len(arr) > i {
*dest[i] = arr[i]
}
}
}
Example http://play.golang.org/p/gJzWp1WglJ
By using this technique, passing any variables are not a problem.
There's nothing built-in but you can write your own function to do something similar:
func unlist(x []string) (string, string) {
return x[0], x[1]
}
a, b := unlist(values);
However, this does mean that there is no way to generalize this which means that you have to write a function for destructuring* every different number and type of argument you need it for.
*note: the general name for this operation is a "destructuring assignment".