是否可以将接口的参数类型留给在Go中实现它的接收器？

Basically I want to have an interface which has a SetParams method, the declaration of which declares it receives one parameter, and the return type of the method, but leaves the return type of the parameter up to the receiver.

Something like this interface:

type ParamsInterface interface {
    SetParams(<someType>) ParamsInterface
}

Now, when XStruct implements it, the type of the parameters is XParams

type XStruct struct {
    params XParams
}

func (x *XStruct) SetParams(params *XParams) ParamsInterface {
    x.params = params
    return x
}

But when YStruct implements it, the type of the parameters is YParams

type YStruct struct {
    params YParams
}

func (y *YStruct) SetParams(params *YParams) ParamsInterface {
    y.params = params
    return y
}

This is called generics, you can only use empty interface interface{} and type casting.

This is doc about generics in go: https://docs.google.com/document/d/1vrAy9gMpMoS3uaVphB32uVXX4pi-HnNjkMEgyAHX4N4/edit#.

This also can help you:

How is the empty interface different than a generic?

Why no generics in Go?

This article suggests some ways how to live without generics: https://appliedgo.net/generics/

Here you can find code generator for generics (in my honest opinion that's not the best idea) https://github.com/cheekybits/genny.