GoLang使用gin调用函数而不传递gin.Context

I've come across a scenario where

func main (c *gin.Context){
    if err := g.Bind(&data); err != nil {
            log.Fatalln(err)
            helper.TraceLog(err)
            helper.Fail(c, helper.INPUT_PARAMS_ERROR, "", err)
            return
    }
}

func Fail(c *gin.Context, errorCode string, result string, message interface{}) {
    response := Response{}
    response.Code = errorCode
    response.Result = message
    response.Message = result

    json.Marshal(response)
    c.JSON(http.StatusBadRequest, response)
}

Is it possible that I do not have to pass gin to Fail func? I've tried every solution I can think of and nothing works.

The reason I'm doing this is to make the code looks more simple and clean.

What I'm looking for is something like this:

    func main (c *gin.Context){
        if err := g.Bind(&data); err != nil {
                log.Fatalln(err)
                helper.TraceLog(err)
                helper.Fail(helper.INPUT_PARAMS_ERROR, "", err)
                return
        }
    }

    func Fail(errorCode string, result string, message interface{}) {
        var c *gin.Context

        response := Response{}
        response.Code = errorCode
        response.Result = message
        response.Message = result

        json.Marshal(response)
        c.JSON(http.StatusBadRequest, response)
    }