func Encode（），编码xml的所有部分

This is code :

import (
"bytes"
"encoding/xml"
"fmt")

func main() {
type body struct {
    Message string `xml:"message"`
}
myXml := body{
    Message:"This is <myText>",
}

    w := &bytes.Buffer{}
        enc := xml.NewEncoder(w)
        enc.Indent("", "  ")
        if err := enc.Encode(myXml); err != nil {
            panic(err)
        }
        request := w.String()
        fmt.Println(request)
    }

Is there any way that the value of field message do not encode.I want not encode. This is result :

<body>
  <message>This is &lt;myText&gt;</message>
</body>

Mission of encoding/xml is to produce valid XML documents. Escaping the < and > characters is a must for a valid XML. Don't worry, the content of <message> will be This is <myText>, but this text must appear as This is &lt;myText&gt; in the source of XML.

Note that using the xml:",innerxml" tag value you could force outputting raw XML data as documented at xml.Marshal():

- a field with tag ",innerxml" is written verbatim, not subject
  to the usual marshaling procedure.

Like this:

type rawxml struct {
    Data string `xml:",innerxml"`
}
type body struct {
    Message rawxml `xml:"message"`
}
myXml := body{
    Message: rawxml{"This is <myText>"},
}

This would output (try it on the Go Playground):

<body>
  <message>This is <myText></message>
</body>

Or implementing and using custom xml.Marshaler, but again, this is invalid XML, this is not what you want. What you have right now is exactly what you want.