I have the following function I'v tried to simplify to just adding a single file to a .zip archive.
Whatever I try, the resulting .zip file has no files listed in it. The size of the archive is correct. But when I try to extract all (windows), the archive is empty.
go version go1.10.1 windows/amd64
func Zip(src string, dst string) error {
destinationFile, err := os.Create(dst)
if err != nil {
return err
}
myZip := zip.NewWriter(destinationFile)
file := `C:\MA\testing\cldeploy-local.json`
zipFile, err := myZip.Create(file)
fsFile, err := os.Open(file)
if err != nil {
return err
}
_, err = io.Copy(zipFile, fsFile)
if err != nil {
return err
}
return nil
if err != nil {
return err
}
err = myZip.Close()
if err != nil {
return err
}
return nil
}
When I extract the file an error message appears: The compressed (zipped) Folder ... is invalid.
As answered by @JimB: file needs to be added as relative path only forward slashes. can not start with slash
func Zip(src string, dst string) error {
destinationFile, err := os.Create(dst)
if err != nil {
return err
}
myZip := zip.NewWriter(destinationFile)
file := `C:\MA\testing\cldeploy-local.json`
// file needs to be added as relative path
// only forward slashes. can not start with slash
relPath := strings.TrimPrefix(file, filepath.Dir(src))
relPath = strings.Replace(relPath, `\`, `/`, -1)
relPath = strings.TrimLeft(relPath, `/`)
zipFile, err := myZip.Create(relPath)
fsFile, err := os.Open(file)
if err != nil {
return err
}
_, err = io.Copy(zipFile, fsFile)
if err != nil {
return err
}
return nil
if err != nil {
return err
}
err = myZip.Close()
if err != nil {
return err
}
return nil
}