Code 2 is base64.Encode of Go. This code uses bit operation many times.
For example,
val := uint(src[si+0])<<16 | uint(src[si+1])<<8 | uint(src[si+2])
And,
val := uint(src[si+0])>>18&0x3F]
I don't know why these bit operations are need to encode to base64. What is the meaning of these bit operations?
Code:
func (enc *Encoding) Encode(dst, src []byte) {
if len(src) == 0 {
return
}
di, si := 0, 0
n := (len(src) / 3) * 3
for si < n {
// Convert 3x 8bit source bytes into 4 bytes
val := uint(src[si+0])<<16 | uint(src[si+1])<<8 | uint(src[si+2])
dst[di+0] = enc.encode[val>>18&0x3F]
dst[di+1] = enc.encode[val>>12&0x3F]
dst[di+2] = enc.encode[val>>6&0x3F]
dst[di+3] = enc.encode[val&0x3F]
si += 3
di += 4
}
remain := len(src) - si
if remain == 0 {
return
}
// Add the remaining small block
val := uint(src[si+0]) << 16
if remain == 2 {
val |= uint(src[si+1]) << 8
}
dst[di+0] = enc.encode[val>>18&0x3F]
dst[di+1] = enc.encode[val>>12&0x3F]
switch remain {
case 2:
dst[di+2] = enc.encode[val>>6&0x3F]
if enc.padChar != NoPadding {
dst[di+3] = byte(enc.padChar)
}
case 1:
if enc.padChar != NoPadding {
dst[di+2] = byte(enc.padChar)
dst[di+3] = byte(enc.padChar)
}
}
}
Here is a commented Javascript implementation of the same algorithm: https://en.wikibooks.org/wiki/Algorithm_Implementation/Miscellaneous/Base64#Javascript
It tells you that this loop:
takes three ASCII chars (8-bit): src[si+0]
, src[si+1]
and src[si+2]
merges them into one 24-bit number (that's val := uint(src[si+0])<<16 | uint(src[si+1])<<8 | uint(src[si+2])
)
re-separate this number into four indices (6-bit) for the base64 character list. (val>>18&0x3F
takes the 18th to 24th bit of the previously calculated number, etc.)
You can also read this: https://en.wikipedia.org/wiki/Base64#Examples