在Golang中将字符串放在两个％之间

I have a string in Golang called mystring and I want to put it between 2 percentages (%mystring%) however until now I wasn't able to do it.

The things that I have tried are:

value := fmt.Sprintf("%%s%",mystring)
value := fmt.Sprintf("%s%s%s","%",mystring,"%")
value := fmt.Sprintf("/% %s/%",mystring)

But when I print it, in the end I receive a nil. Example: the value of mystring is "HelloWorld" then I get: "%HelloWorld%nil"

Right now I am receiving this as result:

/%s/%!(NOVERB)%!(EXTRA string=HelloWorld)<nil>

So, what am I missing? Thanks

You need to escape the %'s in format string using another %:

value := fmt.Sprintf("%%%s%%",mystring)

Use %% in your format string for an actual %.

For example:

func main() {
    mystring := "hello"
    value := fmt.Sprintf("%%%s%%", mystring)
    fmt.Println(value)
}

Prints: %hello%

This is clearly documented at the beginning of the docs for fmt:

%% a literal percent sign; consumes no value