如果您不能为它们分配值，那么Go中的函数指针又有什么用呢？

Can you do anything in Go with a *func()?

    var f func() = foo // works
    var g *func() // works
    g = foo // fails `cannot use foo (type func()) as type *func() in assignment` as expected
    g = &foo // fails too `cannot take the address of foo`

You can't take the address of a function definition, you can take the address of a function value. This works:

g := &f

Playground example: https://play.golang.org/p/BokYCrVmV_p

You can pass it around and set it:

func a(f *func()) {
  *f = foo
}

func main() {
   var f func()

   a(&f)
   f()
}