为什么log.Printf（）无法打印？ [关闭]

I'm learning Go and came across this behavior I don't understand. When I do error checking and use log.Printf() I see the os error that I would normally see if I make that same error on the command line.

But when I use log.Fatal() the last log.Printf() does not print to the screen.

package main

import (
    "log"
    "os/exec"
    "fmt"
)

func main() {
    cmd := exec.Command("ls", "-2")

    stdoutStderr, err := cmd.CombinedOutput()
    if err != nil {
        log.Printf("Error: %v", err)
        fmt.Println("Printing log fatal()")
        log.Fatal(err)
    }
    fmt.Printf("Output %s
", stdoutStderr)

}

I was expecting to see this output:

# go run main.go 
2019/05/14 11:23:34 Error: exit status 2
Output ls: invalid option -- '2'
Try 'ls --help' for more information.
Printing log fatal()
2019/05/14 11:24:45 exit status 2
exit status 1

But My actual result is:

# go run main.go
2019/05/14 11:24:45 Error: exit status 2
Printing log fata()
2019/05/14 11:24:45 exit status 2
exit status 1

log.Fatal calls os.Exit() after printing the log message. So statements after log.Fatal() will not be called. I believe that is the reason you are not seeing output of fmt.Printf("Output %s ", stdoutStderr) in the logs.