遍历XML

I have an XML string

str := "<data><node><value>Foo</value></node></data>"

I need to replace value with another value (Bar). Given a path

"data.node.value"

Is there a way in Go to find and replace that value? So calling Replace(str, "data.node.value","Bar")

<data><node><value>Bar</value></node></data>

I don't think its possible, since you just have a string. You need to

1. Unmarshal the XML into a struct,
2. then manipulate the struct
3. then marshal it back into a string.

Something like this:

package main

import (
    "encoding/xml"
    "fmt"
)

type Data struct {
    Node Node `xml:"node"`
}

type Node struct {
    Value string `xml:"value"`
}

func main() {
    str := "<data><node><value>Foo</value></node></data>"

    var d Data
    xml.Unmarshal([]byte(str), &d)  // unmarshal it

    d.Node.Value = "Bar" // manipulate the struct

    xmlout, _ := xml.Marshal(d) // re-marshal it

    fmt.Println("result: ", string(xmlout))
}