在cgo中不显示printf结果

When I ran this code, I expected to printing result like A: 4, B: 89. But actually, Does not display nothing.

Why this program does not display result to stdout?

main.go:

package main

/*
#include "c.h"

*/
import "C"

import (
    "unsafe"
)

type S struct {
    A int
    B int
}

func main() {
    s := &S{A: 4, B: 89}
    pass_to_c := (*C.S)(unsafe.Pointer(s))
    C.gostruct(pass_to_c)
}

c.h

#include <stdio.h>
#include <stdlib.h>

typedef struct {
    long int A;
    long int B;
} S;

extern void gostruct(S *struct_s) {
    printf("A: %ld, B: %ld
", struct_s->A, struct_s->B);
}

Thanks for comments.

I can got expected result with below codes

main.go:

package main

/*
#include "c.h"

*/
import "C"

import (
    "unsafe"
)

type S struct {
    A int64 // 64bit int
    B int64 // 64bit int 
}

func main() {
    s := &S{A: 4, B: 89}
    pass_to_c := (*C.S)(unsafe.Pointer(s))
    C.gostruct(pass_to_c)
}

c.h:

#include <stdio.h>
#include <stdlib.h>

typedef struct {
    long long int A; // 64bit int
    long long int B; // 64bit int
} S;

extern void gostruct(S *struct_s) {
    printf("{A: %lld, B: %lld}
", struct_s->A, struct_s->B);
}

I suppose struct field must use same type between languages. In question code, struct fields type are not same. (C struct: 32bit int, Go struct: 64bit int)

In answer code, struct field is same between language. (both struct: 64bit int)

Note that My architecture is darwin/amd64