Go函数指针问题[重复]

This question already has an answer here:

My object is not updated even if I use the pointer to a type to update it 3 answers
Golang Operator Overloading 1 answer
Golang changing values of a struct inside a method of another struct 2 answers
Copy instances of type T, when any of the methods of a named type T have a pointer receiver 1 answer

I have a struct

type keeper struct {
    ptr int32
}

then I add a function to it

func(l keeper) next() {
  l.ptr++
}

But when I create a new keeper and call next()

tester := keeper {
  ptr: 0,
}
test.next()

It seems I am not modifying the ptr value within tester. If I change the function to be a pointer it then works

func(l *keeper) next() {
  l.ptr++
}

Why so?

</div>

In Go, a method is just a function that receives an instance of a type. If your function receives an instance as a value, that value is essentially a copy of that instance which will be local to your function and any mutations you make to that instance will not be made to the original instance. If your function receives a pointer to an instance, then any mutations you make will be done directly to the original instance.