I am trying to convert this date string ("2018-10-29T11:48:09.180022-04:00") to ISO format in Go. But not able to do. Can anyone help?
package main
import (
"fmt"
"time"
)
func main() {
l,_ := time.Parse("2006-01-02T15:04:05Z07:00", "2018-10-29T15:18:20-04:00")
fmt.Println(l, time.Now(), time.Now().UTC().Format("2006-01-02T15:04:05Z07:00"))
}
Output:
2018-10-29 15:18:20 -0400 -0400 2009-11-10 23:00:00 +0000 UTC m=+0.000000001 2009-11-10T23:00:00Z
Note that your input string is valid ISO 8601 format.
However, for JSON serialization, JavaScript uses a slightly different (but still completely valid) style of ISO 8601 date format in which only 3 digits are used for fractional seconds (giving millisecond resolution) and the timezone is adjusted to Coordinated Universal Time (UTC), (aka GMT+0, or "Zulu" timezone) designated with a Z
.
// JavaScript
JSON.stringify(new Date()); // => "2018-10-30T15:22:30.293Z"
// Millisecond resolution ─────────────────────────────┺┻┛┃
// "Zulu" (UTC) time zone ────────────────────────────────┚
You can convert your timestamp into the JavaScript style by first parsing the input string, then converting to Zulu time via the UTC()
method, then formatting with the desired output format.
For example (Go Playground):
const (
INPUT_FORMAT = "2006-01-02T15:04:05.999999999-07:00"
OUTPUT_FORMAT = "2006-01-02T15:04:05.000Z"
)
func timestampToJavaScriptISO(s string) (string, error) {
t, err := time.Parse(INPUT_FORMAT, s)
if err != nil {
return "", err
}
return t.UTC().Format(OUTPUT_FORMAT), nil
}
func main() {
s := "2018-10-29T11:48:09.180022-04:00"
s2, err := timestampToJavaScriptISO(s)
if err != nil {
panic(err)
}
fmt.Println(s2)
// 2018-10-29T15:48:09.180Z
}
you can just convert it by using the RFC3339 format:
unitTimeInRFC3339 :=time.Now().Format(time.RFC3339)