如何在golang的开关盒内部定义的函数内部突破开关盒？

The question sounds weird but I didn't know any better way to put it. I am using goquery and I am inside a switch-case:

switch{
    case url == url1:
        doc.Find("xyz").Each(func(i int,s *goquery.Selection){
            a,_ := s.Attr("href")
            if a== b{
                //I want to break out of the switch case right now. I dont want to iterate through all the selections. This is the value.
                break
            }
        })
}

Using break gives the following error: break is not in a loop

What should I use here to break out of the switch-case instead of letting the program iterate over each of the selections and run my function over each of them?

You should make use of goquery's EachWithBreak method to stop iterating over the selection:

switch {
    case url == url1:
        doc.Find("xyz").EachWithBreak(func(i int,s *goquery.Selection) bool {
            a,_ := s.Attr("href")
            return a != b
        })
}

As long as there's no remaining code in your switch case, you do not need to use a break.