I'm confusing about the reassignment of the err
variable for errors in Go.
For example, I tend to be doing this:
err1 := Something()
checkErr(err1)
str, err2 := SomethingElse()
checkErr(err2)
err3 := SomethingAgain()
checkErr(err3)
But I'm always losing track of this and have millions of useless err variables floating around that I don't need, and it makes the code messy and confusing.
But then if I do this:
err := Something()
checkErr(err)
str, err := SomethingElse()
checkErr(err)
err := SomethingAgain()
checkErr(err)
...it gets angry and says err
is already assigned.
But if I do this:
var err error
err = Something()
checkErr(err)
str, err = SomethingElse()
checkErr(err)
err = SomethingAgain()
checkErr(err)
...it doesn't work because str
needs to be assigned with :=
Am I missing something?
you're almost there... at the left side of :=
there needs to be at least one newly create variable. But if you don't declare err
in advance, the compiler tries to create it on each instance of :=
, which is why you get the first error. so this would work, for example:
package main
import "fmt"
func foo() (string, error) {
return "Bar", nil
}
func main() {
var err error
s1, err := foo()
s2, err := foo()
fmt.Println(s1,s2,err)
}
or in your case:
//we declare it first
var err error
//this is a normal assignment
err = Something()
checkErr(err)
// here, the compiler knows that only str is a newly declared variable
str, err := SomethingElse()
checkErr(err)
// and again...
err = SomethingAgain()
checkErr(err)