如何定义接收指针的Go接口方法的实现？

The following program runs fine.

package main

import (
    "fmt"
)

type Person interface {
    Hello()
}

type Joker struct {
    Name string
}

func (j Joker) Hello() {
    fmt.Println(j.Name, "says, \"Hello!\"")
}

func main() {
    var j Joker = Joker{"Peter"}
    invokeHello(j)
}

func invokeHello(p Person) {
    p.Hello()
}

Here is the output.

$ go run foo.go
Peter says, "Hello!"

But when I change the Hello method to receive a pointer, I get errors.

package main

import (
    "fmt"
)

type Person interface {
    Hello()
}

type Joker struct {
    Name string
}

func (j *Joker) Hello() {
    fmt.Println(j.Name, "says, \"Hello!\"")
}

func main() {
    var j *Joker = &Joker{"Peter"}
    invokeHello(j)
}

func invokeHello(p *Person) {
    p.Hello()
}

Here are the errors.

$ go run bar.go
# command-line-arguments
./bar.go:21: cannot use j (type *Joker) as type *Person in argument to invokeHello:
    *Person is pointer to interface, not interface
./bar.go:25: p.Hello undefined (type *Person has no field or method Hello)

How can I fix the second program?

func invokeHello(p *Person) {
    p.Hello()
}

p is type *Person, *Joker implement interface Person, revert invokeHello to:

func invokeHello(p Person) {
    p.Hello()
}

this will fix the second program.

I think you have misleading about golang interface type

An interface type specifies a method set called its interface. A variable of interface type can store a value of any type with a method set that is any superset of the interface. Such a type is said to implement the interface.

Fix

You can't use pointers to interface type. That is the problem:

func invokeHello(p *Person) {
    p.Hello()
}

Should be:

func invokeHello(p Person) {
    p.Hello()
}

Interface implementation

Types implement interfaces. If type has methods appropriate to a methods declared in an interface than the interface is implemented by the type.

Interfaces in Go provide a way to specify the behavior of an object: if something can do this, then it can be used here.

Types vs pointers to a types

Type and *Type are different types. For example *Type could implement an interface but Type can not implement it. But *InterfaceType really has no sence to use.

If you want to receive pointer to a type in a function which expects an interface type, implement the interface with pointer receiver, like you did in a second example.

Example:

type Person interface {
    Hello()
}

type Joker struct {
    Name string
}

/*
A Hello method declared with a pointer receiver which means that a pointer to
the Joker type (*Joker) not Joker type itself implements Person interface.
*/
func (j *Joker) Hello() {
    fmt.Println(j.Name, "says, \"Hello!\"")
}

/*
invokeHello receives ANY type which statisfies Person interface.
In this case this is pointer to Joker type.
*/
func invokeHello(p Person) {
    p.Hello()
}

func main() {
    i := Joker{"Peter"}
    j := &i
    // Note difference between types
    fmt.Printf(
        "Joker type: %s
Pointer to Joker type: %s
",
        reflect.TypeOf(i), reflect.TypeOf(j))
    invokeHello(j)
}

Otherwise if you want to receive a value of a type, implement the interface with value receiver, like you did in a first example.