I want to get all the substrings inside all parentheses in go using Regex.
As an example for the string "foo(bar)foo(baz)golang", i want "bar" and "baz"
in python i can do re.findall("(?<=\()[^)]+(?=\))", "foo(bar)foo(baz)golang")
How to do it in go?
go's regexp package does not support zero width lookarounds. You can leverage captured grouping with the regexp.FindAllStringSubmatch() function:
package main
import (
"regexp"
"fmt"
)
func main() {
str := "foo(bar)foo(baz)golang"
rex := regexp.MustCompile(`\(([^)]+)\)`)
out := rex.FindAllStringSubmatch(str, -1)
for _, i := range out {
fmt.Println(i[1])
}
}
outputs:
bar
baz
The Regex \(([^)]+)\):
\( matches literal (
([^)]+) matches substring upto next ) and put the match in a captured group, here you can use non-greeedy match .*?\) too
\) matches literal )
Try this:
\((.*?)\)
Code Sample:
package main
import (
"regexp"
"fmt"
)
func main() {
var re = regexp.MustCompile(`\((.*?)\)`)
var str = `foo(bar)foo(baz)golang`
mt:= re.FindAllStringSubmatch(str, -1)
for _, i := range mt {
fmt.Println(i[1])
}
}