golang：在方法调用中找到真正的调用者

I have a struct like this :

type Parent struct {
    example string
}
func (p *Parent) GetMyAttr() {
    typ := reflect.TypeOf(p).Elem()

    for i := 0; i < typ.NumField(); i++ {
        p := typ.Field(i)
        if !p.Anonymous {
            fmt.Println(p.Name, ":", p.Type)
        }
    }
}

And if I have another struct like this :

type Child struct {
    Parent
    another string
}

call GetTypeOfMe() in child like this

ch := Child{Parent{"example"},"another"}
ch.GetMyAttr()

is always return example : string . Is this possible to get Child struct in Parent struct with reflection?

Full code is here http://play.golang.org/p/ej4Xh_V2J1

Thanks.

It doesn't work like this, reflect.TypeOf(p).Elem() will always return Parent you have 2 options, either implement GetMyAttr for each child or use a generic function like :

func GetAttr(i interface{}) {
    typ := reflect.Indirect(reflect.ValueOf(i)).Type()
    fmt.Println(typ)
    for i := 0; i < typ.NumField(); i++ {
        p := typ.Field(i)
        fmt.Println(p.Name, ":", p.Type)

    }
}

No, since you operate on a *Parent, not a *Child.
This would "work" (play.golang)

func (p *Child) GetMyAttr() {...

would output:

Parent : main.Parent
another : string

A Parent doesn't know about the struct which might embed it, so the reflection operates only on Parent struct.

You see a similar issue with "Go Reflection with Embedding", which uses interface{} to get to all the struct passed in parameter.