I have been given the following XML structure
<properties>
<property name="element1">data1</property>
<property name="element2">data2</property>
<datetime name="start">13 Jan 2015 14:13:15GMT</datetime>
<property name="element3">data3</property>
<property name="element4">data4</property>
<property name="element5">data5</property>
<categorisation name="category">cat1</categorisation>
<property name="element6">data6</property>
<property name="element7">data7</property>
</properties>
I want to unmarshall it into the following:
type Property string {
Name string
Value string
}
type Properties struct {
Props []Property
DateTime time.Time
Category string
}
but I don't know how to process the out of order Properties
The encoding/xml
package handles that for you. You just have to properly tag your struct fields to tell the xml
package how they are found in the XML source:
type Property struct {
Name string `xml:"name,attr"`
Value string `xml:",cdata"`
}
type Properties struct {
Props []Property `xml:"property"`
DateTime string `xml:"datetime"`
Category string `xml:"categorisation"`
}
Note that I changed the type of DateTime
field to string
because the timestamp in the XML (13 Jan 2015 14:13:15GMT
) does not conform to standard (which would be ISO 8601, in Go layout: 2006-01-02T15:04:05Z07:00
which is time.RFC3339
).
Code to unmarshal:
ps := Properties{}
if err := xml.Unmarshal([]byte(src), &ps); err != nil {
panic(err)
}
fmt.Printf("%+v", ps)
Output (try it on the Go Playground):
{Props:[{Name:element1 Value:data1} {Name:element2 Value:data2} {Name:element3 Value:data3}
{Name:element4 Value:data4} {Name:element5 Value:data5} {Name:element6 Value:data6}
{Name:element7 Value:data7}] DateTime:13 Jan 2015 14:13:15GMT Category:cat1}
You can see that Props
properly contains all 7 properties in correct order even though <datetime>
and <categorisation>
tags are inserted between them.