I am developing a go package, which is a little bit complex and thus I want to organize the source code into multiple directories.
However, I don't want the users of the package to have to use too long imports. Anyways, the internal structure of the package isn't their concern.
Thus, my package structure looks so:
subDir1
subSubDir1
subSubDir2
subDir2
subSubDir3
...and so on. All of them have their exported calls.
I would like to avoid that my users have to import
import (
"mypackage/subDir1"
"mypackage/subDir1/subSubDir2"
)
...and so on.
I only want, if they want to use an exported function from my package, they should have access all of them by simply importing mypackage.
I tried that I declare package mypackage in all of the .go files. Thus, I had source files in different directories, but with the same package declaration.
In this case, the problem what I've confronted was that I simply couldn't import multiple directories from the same package. It said:
./src1.go:6:15: error: redefinition of ‘mypackage’
"mypackage/mysubdir1"
^
./src1.go:4:10: note: previous definition of ‘mypackage’ was here
"mypackage"
^
./src1.go:5:15: error: redefinition of ‘mypackage’
"mypackage/mysubdir2"
^
./src1.go:4:10: note: previous definition of ‘mypackage’ was here
"mypackage"
^
Is it somehow possible?
You should not do this in any case, as the language spec allows a compiler implementation to reject such constructs. Quoting from Spec: Package clause:
A set of files sharing the same PackageName form the implementation of a package. An implementation may require that all source files for a package inhabit the same directory.
Instead "structure" your file names to mimic the folder structure; e.g. instead of files of
foo/foo1.go
foo/bar/bar1.go
foo/bar/bar2.go
You could simply use:
foo/foo1.go
foo/bar-bar1.go
foo/bar-bar2.go
Also if your package is so big that you would need multiple folders to even "host" the files of the package implementation, you should really consider not implementing it as a single package, but break it into multiple packages.
Also note that Go 1.5 introduced internal packages. If you create a special internal subfolder inside your package folder, you may create any number of subpackages inside that (even using multiple levels). Your package will be able to import and use them (or to be more precise all packages rooted at your package folder), but no one else outside will be able to do so, it would be a compile time error.
E.g. you may create a foo package, have a foo/foo.go file, and foo/internal/bar package. foo will be able to import foo/internal/bar, but e.g. boo won't. Also foo/baz will also be able to import and use foo/internal/bar because it's rooted at foo/.
So you may use internal packages to break down your big package into smaller ones, effectively grouping your source files into multiple folders. Only thing you have to pay attention to is to put everything your package wants to export into the package and not into the internal packages (as those are not importable / visible from the "outside").
Inside your package source code, you have to differentiate your source directories by renamed imports. You can declare the same package mypackage in all of your source files (even if they are in different directories).
However, while you import them, you should give an induvidual names to the directories. In your source src1.go, import the other directories on this way:
import (
"mypackage"
submodule1 "mypackage/mySubDir"
)
And you will be able to reach the API defined in "mypackage" as mypackage.AnyThing(), and the API defined in mySubDir as submodule1.AnyThing().
The external world (i.e. the users of your package) will see all exported entities in myPackage.AnyThing().
Avoid namespace collisions. And use better understable, intuitive naming as in the example.
Yes, this is doable without any problems, just invoke the Go compiler by hand, that is not via the go tool.
But the best advice is: Don't do that. It's ugly and unnecessarily complicated. Just design your package properly.