Golang / gin从gin.Context解析JSON

我从gin文档中了解到，可以将json绑定到类似的结构中

type Login struct {
    User     string `form:"user" json:"user" binding:"required"`
    Password string `form:"password" json:"password" binding:"required"`
}

func main() {
    router := gin.Default()

    // Example for binding JSON ({"user": "manu", "password": "123"})
    router.POST("/loginJSON", func(c *gin.Context) {
        var json Login
        if c.BindJSON(&json) == nil {
            if json.User == "manu" && json.Password == "123" {
                c.JSON(http.StatusOK, gin.H{"status": "you are logged in"})
            } else {
                c.JSON(http.StatusUnauthorized, gin.H{"status": "unauthorized"})
            }
        }
    })
}

你总是需要构建一个绑定JSON的结构。 但是，如果有一个非常复杂的JSON数据，那么仅获得其中的一部分，创建一个复杂的结构便是一个很大的负担。 那可以避免id并直接解析吗？

You don't need to create a struct for all the fields present in the JSON response, only the fields you are interested in. Any other fields present in the response will be ignored when unmarshaling.

You can also unmarshal to a generic map[string]interface{} but this is only really useful for truly dynamic data. If you know the format of the response ahead of time you will nearly always be best to create a custom struct to get type safety and avoid continual nil checks when accessing the map. Additionally, a targeted struct avoids storing unnecessary values when JSON in unmarshalled.

You can use the JSON to Go tool to help quickly create a struct definition from a JSON response. You could then easily strip out all the fields you don't need.