如何提取Unix时间戳并获取日期

I have an integer

x := 1468540800

I want to fetch the date out of this unix timestamp in Golang. I have tried time.ParseDuration but looks like that's not the correct way to extract date out of this. Converstion should happen like this http://www.unixtimestamp.com/index.php
I intend to convert into in ISO 8601 format may be. I want string like 2016-09-14.

You may use t := time.Unix(int64(x), 0) with location set to local time.
Or use t := time.Unix(int64(x), 0).UTC() with the location set to UTC.

You may use t.Format("2006-01-02") to format, Code (try on The Go Playground):

package main

import (
    "fmt"
    "time"
)

func main() {
    x := 1468540800
    t := time.Unix(int64(x), 0).UTC() //UTC returns t with the location set to UTC.
    fmt.Println(t.Format("2006-01-02"))
}

output:

2016-07-15

Use time.Unix with nanoseconds set to 0.

t := time.Unix(int64(x), 0)

Playground: https://play.golang.org/p/PpOv8Xm-CS.

$timestamp=1468540800;
echo gmdate("Y-m-d", $timestamp);

You can use strconv.ParseInt() for parsing to int64 in combination with time.Unix.

myTime,errOr := strconv.ParseInt(x, 10, 64)
    if errOr != nil {
        panic(errOr)
    }
    newTime := time.Unix(myTime, 0)