I am new to GO code and am having some issues formatting string variables with multiple (carriage returns) in it. I have a string variable that has stored in it the following:
"1. Check the connections 2. Have the firewall settings been checked 3. Check switch/network connections 4. Contact admin"
Now, I want to print the line so that it looks like this:
Remedy: 1. Check the connections
2. Have the firewall setting been checked
3. Check switch/network connections
4. Contact admin
However, in my program when I run the output line:
fmt.Println("remedy:\t\t\t\t" + alt.Remedy)
It comes up like this:
remedy: 1. Check the connections
2. Have the firewall settings been checked
3. Check switch/network connections
4. Contact admin
How do I get it so that by issuing that command, all 4 options are listed in the same column? In this example, I want options 2, 3, and 4 listed under the #1 option.
Thanks in advance!
There's nothing in Go to do this for you.
Instead, you can split the string into lines and format them accordingly.
Here is an example:
package main
import (
"fmt"
"strings"
)
func main() {
str := "1. Check the connections
2. Have the firewall settings been checked
3. Check switch/network connections
4. Contact admin"
// Split the string into lines.
parts := strings.Split(str, "
")
// Iterate over the lines.
for i, s := range parts {
if i == 0 {
// First line: start with "Remedy"
fmt.Printf("Remedy:\t\t\t%s
", s)
} else {
fmt.Printf(" \t\t\t%s
", s)
}
}
}
This outputs:
Remedy: 1. Check the connections
2. Have the firewall settings been checked
3. Check switch/network connections
4. Contact admin
Note: there are probably a few other ways to do this, I just picked this one.
Since you are storing the "remedies" together in a string, there isn't much you can do other than include spacing in your string var.
"1. Check the connections
\t\t\t\t2. Have the firewall settings been checked
\t\t\t\t3. Check switch/network connections
\t\t\t\t4. Contact admin"
I would suggest saving them as a slice and iterating to print:
package main
import "fmt"
var remedy = []string{
"Check the connections",
"Have the firewall settings been checked",
"Check switch/network connections",
"Contact admin",
}
func main() {
fmt.Print("remedy:")
for i := range remedy {
if i == 0 {
fmt.Printf("%13d. %s
", i+1, remedy[i])
continue
}
fmt.Printf("%20d. %s
", i+1, remedy[i])
}
}
The Go Programming Language Specification
A string literal represents a string constant obtained from concatenating a sequence of characters. There are two forms: raw string literals and interpreted string literals.
Raw string literals are character sequences between back quotes, as in
foo. Within the quotes, any character may appear except back quote. The value of a raw string literal is the string composed of the uninterpreted (implicitly UTF-8-encoded) characters between the quotes; in particular, backslashes have no special meaning and the string may contain newlines. Carriage return characters ('') inside raw string literals are discarded from the raw string value.
Use a raw string literal. For example,
package main
import (
"fmt"
)
func main() {
message := `
Remedy: 1. Check the connections
2. Have the firewall setting been checked
3. Check switch/network connections
4. Contact admin
`
fmt.Print(message[1:])
}
Playground: https://play.golang.org/p/pdgAoYnBIch
Output:
Remedy: 1. Check the connections
2. Have the firewall setting been checked
3. Check switch/network connections
4. Contact admin
Similar to Marc's answer, but I would do it this way. It's simpler, shorter and cleaner:
Replace each newline character in the source string with a newline plus the indentation that non-first lines need. You may use strings.Replace() for this.
The source string to be formatted:
s := "1. Check the connections 2. Have the firewall settings been checked 3. Check switch/network connections 4. Contact admin"
And the formatting is a simple line:
fmt.Println("Remedy: ", strings.Replace(s, "
", "
", -1))
Output (try it on the Go Playground):
Remedy: 1. Check the connections
2. Have the firewall settings been checked
3. Check switch/network connections
4. Contact admin