I split a string by spaces:
splstr = strings.Split(str, " ")
Then I iterate each word, and look at the first character like this:
splstr[i][0] == "#"
But I got these errors from that line:
... : cannot convert "#" to type uint8
... : invalid operation: splstr[i][0] == "#" (mismatched types uint8 and string)
But then I spliced it:
splstr[i][:1] == "#"
And that works. I get why [:1] is of type string, but why is [0] of type uint8? (I'm using Go 1.1.)
Because the array notation on a string gives access to the string's bytes, as documented in the language spec:
http://golang.org/ref/spec#String_types
A string's bytes can be accessed by integer indices 0 through len(s)-1.
(byte is an alias for uint8)
[x:x] ([:x] is a form of [0:x]) will cut a slice into another slice while [x] will retrieve the object at index x. The difference is shown below:
arr := "#####"
fmt.Println(arr[:1]) // will print out a string
fmt.Println(arr[0]) // will print out a byte
If the string is converted into []byte:
arr := []byte("#####")
fmt.Println(arr[:1]) // will print out a slice of bytes
fmt.Println(arr[0]) // will print out a byte
You can try this yourself at http://play.golang.org/p/OOZQqXTaYK