如何在golang中将字符串值作为json对象返回？

I am using golang with beego framework and I have problem with serving strings as json.

EventsByTimeRange returns a string value in json format

this.Data["json"] = dao.EventsByTimeRange(request) // this -> beego controller
this.ServeJson()

"{\"key1\":0,\"key2\":0}"

How can I get rid of quotation marks?

you can re-define your json format string in a new type. this is a small demo

package main

import (
    "encoding/json"
    "fmt"
)

type JSONString string

func (j JSONString) MarshalJSON() ([]byte, error) {
    return []byte(j), nil
}

func main() {
    s := `{"key1":0,"key2":0}`
    content, _ := json.Marshal(JSONString(s))
    fmt.Println(_, string(content))
}   

in your case you can write like this

this.Data["json"] = JSONString(dao.EventsByTimeRange(request))
this.ServeJson()   

BTW,golang-json package adds quotation marks because it treats your string as a json value,not a json k-v object.

The string you got is a fine JSON formatted value. all you need is to unmarshal it into a correct type.

See below code.

However, I think you misunderstood the ServeJson(), it returns a JSON formatted string which your client will use it, and it does that just fine (see your question).

If you remove the qoutes and slashes, You'll end up with invalid JSON string!

package main

import "fmt"
import "log"
import "encoding/json"
func main() {
    var b map[string]int
    err := json.Unmarshal ([]byte("{\"key1\":0,\"key2\":0}"), &b)
    if err != nil{
        fmt.Println("error: ", err)
    }
    log.Print(b)
    log.Print(b["key1"])
}

You'll get: map[key1:0 key2:0]