Let's say I want to run 'ls' in a go program, and store the results in a string. There seems to be a few commands to fork processes in the exec and os packages, but they require file arguments for stdout, etc. Is there a way to get the output as a string?
Edit: This answer is obsolete. Please see Fatih Arslan's answer below.
Use exec.Run by specifying Pipe as the stdout (and stderr if you want). It will return cmd, which contains an os.File in the Stdout (and Stderr) fields. Then you can read it using for example ioutil.ReadAll.
Example:
package main
import (
"exec";
"io/ioutil";
)
func main() {
if cmd, e := exec.Run("/bin/ls", nil, nil, exec.DevNull, exec.Pipe, exec.MergeWithStdout); e == nil {
b, _ := ioutil.ReadAll(cmd.Stdout)
println("output: " + string(b))
}
}
Use exec.Run, passing Pipe for stdout. Read from the pipe that it returns.
Two options, depending on the paradigm you prefer:
There is an easier way now:
package main
import (
"fmt"
"log"
"os/exec"
)
func main() {
out, err := exec.Command("date").Output()
if err != nil {
log.Fatal(err)
}
fmt.Printf("The date is %s
", out)
}
Where out is the standart output. It's in the format []byte, but you can change it to string easily with:
string(out)
You can also use CombinedOutput() instead of Output() which returns standard output and standard error.
To get both stdout and stderr into separate strings, you can use byte buffers like so:
cmd := exec.Command("date")
var outb, errb bytes.Buffer
cmd.Stdout = &outb
cmd.Stderr = &errb
err := cmd.Run()
if err != nil {
log.Fatal(err)
}
fmt.Println("out:", outb.String(), "err:", errb.String())
I used this with a recent version of GO (~1.11)
// CmdExec Execute a command
func CmdExec(args ...string) (string, error) {
baseCmd := args[0]
cmdArgs := args[1:]
log.Debugf("Exec: %v", args)
cmd := exec.Command(baseCmd, cmdArgs...)
out, err := cmd.Output()
if err != nil {
return "", err
}
return string(out), nil
}
// Usage:
// out, err := CmdExec("ls", "/home")