将javascript变量传递给php？

ok so im trying to get a javascript variable into a php script, this would be an example,

<script type="text/javascript">
x = new Date()
</script>
<?php
$x = $_GET["x"]; 
?>
<p><?php echo $x ?></p>

i just cant get it to work! I need help please?

EDIT: well im just trying to get the hash from a url via javascript then put that in a php script.

PHP and javascript don't work like that.

PHP is a server-side language. While javascript is a clientside language.

There are still ways of passing data from the client-window to your server, via ajax, query parameters, cookies... But none will work in the same page.

Give us a clearer image on what you are trying to achieve and we will gladly help.

UPDATE

JS

<script type="text/javascript">  
    document.cookie = 'name=Khez' ;  
</script>  

PHP

<?php  
    var_dump($_COOKIE['name']);  
?>  

PHP is "Server Side" code and javascript is client side code. They don't interact...

PHP is server-side~ all parsing is done on the server. JavaScript is client-side~ everything happens AFTER it get's to the client. If you need date in PHP, I recommend time() and or date()

So there are 2 pages page1.php and page2.php

page2.php needs to pass JS variables to page1.php

We can do this by passing it as url variables from page2.php and get it in page1.php using $_GET[].

page2.php (send JS variable)

<script type=text/javascript>
  var lati = location.lat();
  var longi = location.lng();
  document.location = 'http://www.rajak.me/index.php?addlat='+lati+'&addlong='+longi;   
});
</script>

page1.php (receive JS variable)

<?php    
  $addlat = $_GET['addlat'];
  $addlong = $_GET['addlong'];
?>

You could use the following Javascript which will link to somepage.php with the variable in the Url

<script type="text/javascript">
x = new Date()
window.location.href = "somepage.php?w1=" + x;
</script>

This is the contents of somepage.php which recieves the variable and echoes it

<?php
   if (isset($_GET["w1"])) {
     $x = $_GET["w1"];
     echo $x;
   }else{
   echo 'no variable received';
   }
    ?>